Analog Electronics Technique(Huazhong University of Science and Technology) 中国大学慕课答案2024完整版100分

思骏问摩恰槽任肪揭梅稼奸然

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起止时间:2020-05-11到2020-09-20
更新状态:已完结

Lecture 1 The Bipolar Junction Transistor Test questions for the bipolar junction transistor

1、 When a BJT transistor is used as an amplifying device, the base-emitter junction is ( ) biased, and the base-collector junction is ( ) biased.

A:Forward，forward
B:Reverse, reverse
C:Forward, reverse
D:Reverse, forward
答案: Forward, reverse

2、 For the impurity doping concentrations in the three regions of the BJT, which region is the highest ( )

A:base
B:emitter
C:collect‍or
D:unidentified
答案: emitter

3、 When a BJT transistor worked in saturation region, the base-emitter junction is ( ) biased, and the base-collector junction is ( ) biased.

A:Forward，forward
B:Reverse, reverse
C:Forward, reverse
D:Reverse, forward
答案: Forward，forward

4、 When a BJT transistor worked in cutoff region, the base-emitter junction is ( ) biased, and the base-collector junction is ( ) biased.

A:Forward，forward
B:Reverse, reverse‍
C:Forward, reverse
D:Reverse, forward
答案: Reverse, reverse‍

5、 For the impurity doping concentrations in the three regions of the BJT, which region is the lowest ( )

A:base
B:emitter‍
C:collector‍
D:unidentified
答案: base

6、 ‍A transistor is biased in the forward-active mode, the current of the three terminals are I1= –1.2mA, I2= –0.03mA, I3= 1.23mA，which of these is the emitter terminal ( )

A:1
B:2
C:3
D:unidentified
答案: 3

7、 A transistor is biased in the forward-active mode, the current of the three terminals are I1= –1.2mA, I2= –0.03mA, I3= 1.23mA，which of these is the base terminal ( )

A:1
B:2
C:3
D:unidentified
答案: 2

8、 A transistor is biased in the forward-active mode, the current of the three terminals are I1= –1.2mA, I2= –0.03mA, I3= 1.23mA，the current gain β is ( )‍

A:30
B:40
C:41
D:1.23
答案: 40

9、 In a BJT circuit, the transistor are made of silicon, and the voltage values for three terminals are given, which BJT operates in forward-active mode ( )

A:VC=6V ,VB=0.7V, VE=0V
B:VC=6V , VB=6V , VE=5.4V
C:VC=6V ,VB=4V ,VE=3.6V
D:VC=3.6V ,VB=4V ,VE=3.4V
答案: VC=6V ,VB=0.7V, VE=0V

10、 In a BJT circuit, the transistor are made of silicon, and the voltage values for three terminals are given, which BJT operates in cutoff region ( )

A:VC=6V ,VB=0.7V, VE=0V
B:VC=6V , VB=6V , VE=5.4V
C:VC=6V ,VB=4V ,VE=3.6V
D:VC=3.6V ,VB=4V ,VE=3.4V
答案: VC=6V ,VB=4V ,VE=3.6V

11、 In the amplification circuit, the BJT is worked in forward-active region, and the voltage of each terminals is V1=2V, V2=6V and V3=2.7V, for the three terminals, which is the emitter ( ), the type of this transistor is ( ).

A:3, NPN
B:2, PNP
C:1,NPN
D:1, PNP‍
答案: 1,NPN

12、 For the circuit shown in Figure 13, which region does the transistor work in ( )‍

A:Forward-active region
B: Saturation region
C:Cutoff region
D:unidentified
答案: Saturation region

13、 For the circuit shown in Figure, which region does the transistor work in ( )

A:Forward-active region
B:Saturation region
C:Cutoff region
D:unidentified
答案: Forward-active region

14、 For the circuit shown in Figure , if the input signal is a good sinusoidal signal, but the output waveform is in the Figure 16, so this is which distortion ( )

A:Saturation and Cutoff distortion
B:Saturation distortion‍
C:Cutoff distortion
D:unidentified
答案: Saturation distortion‍

15、 For the circuit shown in Figure, which region does the transistor work in ( )

A:Forward-active region
B:Saturation region
C:Cutoff region
D:unidentified
答案: Forward-active region

16、 In a BJT circuit, the transistor are made of silicon, and the voltage values for three terminals are given, which BJT operates in saturation region ( )‍

A:VC=6V ,VB=0.7V, VE=0V
B:VC=6V , VB=6V , VE=5.4V‍
C:VC=6V ,VB=4V ,VE=3.6V
D:VC=3.6V ,VB=4V ,VE=3.4V
答案: VC=6V , VB=6V , VE=5.4V‍;
VC=3.6V ,VB=4V ,VE=3.4V

17、 For the circuit shown in Figure , if the input signal is a good sinusoidal signal, but the output waveform is in the Figure, so what measures can be taken to eliminate such distortion ( )

A:increase VCC amplitude
B:reduce the amplitude of signal source
C:reduce the value of load resistance RL
D:open the load
答案: increase VCC amplitude;
reduce the amplitude of signal source;
reduce the value of load resistance RL