(-0.044,0.344)B:

划畔匠笨党胯遁麓卢革魄舰绷

纲搅瞄洽红措砂粹谋擞绰富让

(-0.044,0.344)B:

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(-0.044,0.344)B:第1张

(-0.044,0.344)B:第2张

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设总体X存在二阶矩,(-0.044,0.344)B:第3张

(-0.044,0.344)B:第4张

,求(-0.044,0.344)B:第3张

(-0.044,0.344)B:第6张

的相关系数( )。
A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第8张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第11张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第13张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第15张

答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第11张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第20张

是从均匀分布(-0.044,0.344)B:第3张

(-0.044,0.344)B:第22张

抽取的样本,则样本均值(-0.044,0.344)B:第3张

(-0.044,0.344)B:第24张

的渐进分布为( )。
A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第26张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第29张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第31张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第34张

答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第34张

设总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第39张

,样本(-0.044,0.344)B:第3张

(-0.044,0.344)B:第41张

,概率(-0.044,0.344)B:第3张

(-0.044,0.344)B:第43张

( )。
A:0.4215
B:0.5785
C:0.1587
D:0.8413
答案: 0.5785

设总体以等概率取1,2,3,4,5,现从中抽取样本容量为4的一组样本,则事件(-0.044,0.344)B:第3张

(-0.044,0.344)B:第45张

的概率.( )
A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第47张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第49张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第51张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第54张

答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第54张

总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第59张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第61张

未知,抽取样本容量为25的样本,样本的标准差s=7.2674,(-0.044,0.344)B:第3张

(-0.044,0.344)B:第63张

等于 ( ).
A:0.95
B:0.975
C:0.05
D:0.025
答案: 0.05

从总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第66张

抽取样本容量都为n的两组样本,其样本均值分别为(-0.044,0.344)B:第3张

(-0.044,0.344)B:第68张

,概率(-0.044,0.344)B:第3张

(-0.044,0.344)B:第70张

,则最小的样本容量n为( )。
A:6
B:7
C:8
D:9
答案: 8

设总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第66张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第75张

为样本,(-0.044,0.344)B:第3张

(-0.044,0.344)B:第77张

为样本均值和样本方差,(-0.044,0.344)B:第3张

(-0.044,0.344)B:第79张

的分布为( )。
A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第29张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第84张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第87张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第89张

答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第87张

设总体X服从正态分布(-0.044,0.344)B:第3张

(-0.044,0.344)B:第94张

,总体Y服从正态分布(-0.044,0.344)B:第3张

(-0.044,0.344)B:第96张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第98张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第100张

分别是来自总体X和Y的简单随机样本,则
(-0.044,0.344)B:第3张

(-0.044,0.344)B:第102张

( )。
A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第104张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第106张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第109张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第111张

答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第109张

如果观测到样本(-0.044,0.344)B:第3张

(-0.044,0.344)B:第116张

的一组观测值为-10,2,7,-5,4,0,9,12,-3,1,那么该组样本的中位数为( )。
A:4
B:1
C:2
D:2.5
答案: 2.5

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第118张

A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第121张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第123张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第125张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第127张

答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第121张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第133张

为总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第137张

的简单随机样本,(-0.044,0.344)B:第3张

(-0.044,0.344)B:第139张


(-0.044,0.344)B:第3张

(-0.044,0.344)B:第141张

,则有( )。
A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第147张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第153张

的有偏估计量,(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第159张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第165张

的无偏估计量 
B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第147张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第153张

的无偏估计量,(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第159张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第165张

的有偏估计量 
C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第147张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第153张

的有偏估计量,(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第159张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第165张

的有偏估计量
D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第147张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第153张

的无偏估计量,(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第159张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第165张

的无偏估计量   
答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第147张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第153张

的无偏估计量,(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第159张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第165张

的无偏估计量   

设随机变量的X的分布函数为
(-0.044,0.344)B:第3张

(-0.044,0.344)B:第263张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第133张

为总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第137张

的简单随机样本,则(-0.044,0.344)B:第3张

(-0.044,0.344)B:第272张

的极大似然估计量为( )。
A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第274张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第276张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第279张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第281张

答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第279张

设总体概率函数为
(-0.044,0.344)B:第3张

(-0.044,0.344)B:第286张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第290张

为总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第137张

的简单随机样本,则(-0.044,0.344)B:第3张

(-0.044,0.344)B:第296张

的矩估计为( )。
A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第298张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第300张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第303张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第305张

答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第303张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第310张

是来自均匀分布总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第312张

的样本,则(-0.044,0.344)B:第3张

(-0.044,0.344)B:第314张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第316张

的无偏估计。( )
A:错
B:对
答案: 错

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第290张

为泊松分布总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第322张

的简单随机样本,其中(-0.044,0.344)B:第3张

(-0.044,0.344)B:第324张

未知,令(-0.044,0.344)B:第3张

(-0.044,0.344)B:第326张

,则(-0.044,0.344)B:第3张

(-0.044,0.344)B:第328张

的极大似然估计为( )。
A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第331张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第333张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第335张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第337张

答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第331张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第290张

为均匀分布总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第346张

的简单随机样本,其中(-0.044,0.344)B:第3张

(-0.044,0.344)B:第348张

未知,则(-0.044,0.344)B:第3张

(-0.044,0.344)B:第350张

的极大似然估计为( )。
A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第353张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第355张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第357张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第359张

答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第353张

设总体为0-1分布(-0.044,0.344)B:第3张

(-0.044,0.344)B:第364张

,则(-0.044,0.344)B:第3张

(-0.044,0.344)B:第366张

的无偏估计的方差的C-R下界为( )。
A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第368张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第371张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第373张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第375张

答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第371张

总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第381张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第383张

为X的样本,样本均值和样本方差为(-0.044,0.344)B:第3张

(-0.044,0.344)B:第385张

,若(-0.044,0.344)B:第3张

(-0.044,0.344)B:第387张

未知,求(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第390张

对应于置信度为(-0.044,0.344)B:第3张

(-0.044,0.344)B:第392张

的置信区间.( )

A:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第395张

B:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第397张

C:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第399张

D:(-0.044,0.344)B:第3张

(-0.044,0.344)B:第401张

        
答案: (-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第395张

总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第381张

,现从总体(-0.044,0.344)B:第3张

(-0.044,0.344)B:第409张

中抽取容量为9的样本,经观测与计算得样本均值(-0.044,0.344)B:第3张

(-0.044,0.344)B:第411张

,样本均方差(-0.044,0.344)B:第3张

(-0.044,0.344)B:第413张

.若(-0.044,0.344)B:第3张

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第390张

未知,求(-0.044,0.344)B:第3张

(-0.044,0.344)B:第418张

对应于置信度为0.95的置信区间.( )
A:(0.019,0.151)
B:(0.017,0.122)
答案: (0.019,0.151)

(-0.044,0.344)B:第3张

(-0.044,0.344)B:第420张

A:

(-0.044,0.344)

B:

(-0.064,0.844)

答案:

(-0.044,0.344)



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